1 00:00:00,000 --> 00:00:00,540 2 00:00:00,540 --> 00:00:04,520 Use completing the square to write the quadratic equation y 3 00:00:04,520 --> 00:00:09,390 is equal to negative 3x squared, plus 24x, minus 27 in 4 00:00:09,390 --> 00:00:12,920 vertex form, and then identify the vertex. 5 00:00:12,920 --> 00:00:15,340 So we'll see what vertex form is, but we essentially 6 00:00:15,340 --> 00:00:18,880 complete the square, and we generate the function, or we 7 00:00:18,880 --> 00:00:23,440 algebraically manipulate it so it's in the form y is equal to 8 00:00:23,440 --> 00:00:29,970 A times x minus B squared, plus C. 9 00:00:29,970 --> 00:00:32,390 We want to get the equation into this form right here. 10 00:00:32,390 --> 00:00:37,450 This is vertex form right there. 11 00:00:37,450 --> 00:00:40,770 And once you have it in vertex form, you'll see that you can 12 00:00:40,770 --> 00:00:44,280 identify the x value of the vertex as what value will make 13 00:00:44,280 --> 00:00:45,790 this expression equal to 0. 14 00:00:45,790 --> 00:00:47,740 So in this case it would be B. 15 00:00:47,740 --> 00:00:52,540 And the y value of the vertex, if this is equal to 0, then 16 00:00:52,540 --> 00:00:54,590 the y value is just going to be C. 17 00:00:54,590 --> 00:00:55,470 And we're going to see that. 18 00:00:55,470 --> 00:00:58,480 We're going to understand why that is the vertex, why this 19 00:00:58,480 --> 00:01:00,310 vertex form is useful. 20 00:01:00,310 --> 00:01:02,310 So let's try to manipulate this equation to get 21 00:01:02,310 --> 00:01:03,650 it into that form. 22 00:01:03,650 --> 00:01:06,060 So if we just rewrite it, the first thing that immediately 23 00:01:06,060 --> 00:01:09,490 jumps out at me, at least, is that all of these numbers are 24 00:01:09,490 --> 00:01:10,790 divisible by negative 3. 25 00:01:10,790 --> 00:01:13,170 And I just always find it easier to manipulate an 26 00:01:13,170 --> 00:01:15,920 equation if I have a 1 coefficient out in front of 27 00:01:15,920 --> 00:01:16,680 the x squared. 28 00:01:16,680 --> 00:01:18,390 So let's just factor out a negative 3 29 00:01:18,390 --> 00:01:19,670 right from the get-go. 30 00:01:19,670 --> 00:01:25,040 So we can rewrite this as y is equal to negative 3 times x 31 00:01:25,040 --> 00:01:30,470 squared, minus 8x-- 24 divided by negative 3 is 32 00:01:30,470 --> 00:01:32,752 negative 8-- plus 9. 33 00:01:32,752 --> 00:01:36,790 Negative 27 divided by negative 3 is positive 9. 34 00:01:36,790 --> 00:01:40,410 Let me actually write the positive 9 out here. 35 00:01:40,410 --> 00:01:42,950 You're going to see in a second why I'm doing that. 36 00:01:42,950 --> 00:01:46,020 Now, we want to be able to express part of this 37 00:01:46,020 --> 00:01:47,290 expression as a perfect square. 38 00:01:47,290 --> 00:01:48,950 That's what vertex form does for us. 39 00:01:48,950 --> 00:01:52,170 We want to be able to express part of this expression as a 40 00:01:52,170 --> 00:01:53,160 perfect square. 41 00:01:53,160 --> 00:01:54,525 Now how can we do that? 42 00:01:54,525 --> 00:01:57,650 Well, we have an x squared minus 8x. 43 00:01:57,650 --> 00:02:01,250 So if we had a positive 16 here-- because, well, just 44 00:02:01,250 --> 00:02:03,675 think about it this way, if we had negative 8, you divide it 45 00:02:03,675 --> 00:02:05,160 by 2, you get negative 4. 46 00:02:05,160 --> 00:02:08,110 You square that, it's positive 16. 47 00:02:08,110 --> 00:02:09,870 So if you had a positive 16 here, this would 48 00:02:09,870 --> 00:02:10,639 be a perfect square. 49 00:02:10,639 --> 00:02:13,450 This would be x minus 4 squared. 50 00:02:13,450 --> 00:02:17,300 But you can't just willy-nilly add a 16 there, you would 51 00:02:17,300 --> 00:02:20,075 either have to add a similar amount to the other side, and 52 00:02:20,075 --> 00:02:22,000 you would have to scale it by the negative 3 and all of 53 00:02:22,000 --> 00:02:25,580 that, or, you can just subtract a 16 right here. 54 00:02:25,580 --> 00:02:26,840 I haven't changed the expression. 55 00:02:26,840 --> 00:02:28,630 I'm adding a 16, subtracting a 16. 56 00:02:28,630 --> 00:02:29,370 I've added a 0. 57 00:02:29,370 --> 00:02:30,770 I haven't it changed it. 58 00:02:30,770 --> 00:02:36,890 But what it allows me to do is express this part of the 59 00:02:36,890 --> 00:02:39,160 equation as a perfect square. 60 00:02:39,160 --> 00:02:43,830 That right there is x minus 4 squared. 61 00:02:43,830 --> 00:02:46,240 And if you're confused, how did I know it was 16? 62 00:02:46,240 --> 00:02:48,720 Just think, I took negative 8, I divided by 2, I 63 00:02:48,720 --> 00:02:49,980 got negative 4. 64 00:02:49,980 --> 00:02:51,300 And I squared negative 4. 65 00:02:51,300 --> 00:02:53,640 This is negative 4 squared right there. 66 00:02:53,640 --> 00:02:56,790 And then I have to subtract that same amount so I don't 67 00:02:56,790 --> 00:02:58,130 change the equation. 68 00:02:58,130 --> 00:03:00,190 So that part is x minus 4 squared. 69 00:03:00,190 --> 00:03:06,190 And then we still have this negative 3 hanging out there. 70 00:03:06,190 --> 00:03:11,690 And then we have negative 16 plus 9, which is negative 7. 71 00:03:11,690 --> 00:03:13,230 So we're almost there. 72 00:03:13,230 --> 00:03:15,860 We have y equal to negative 3 times this whole thing, not 73 00:03:15,860 --> 00:03:16,350 quite there. 74 00:03:16,350 --> 00:03:17,880 To get it there, we just multiply negative 3. 75 00:03:17,880 --> 00:03:21,480 We distribute the negative 3 on to both of these terms. So 76 00:03:21,480 --> 00:03:26,820 we get y is equal to negative 3 times x, minus 4 squared. 77 00:03:26,820 --> 00:03:32,390 And negative 3 times negative 7 is positive 21. 78 00:03:32,390 --> 00:03:35,520 So we have it in our vertex form, we're done with that. 79 00:03:35,520 --> 00:03:38,860 And if you want to think about what the vertex is, I told you 80 00:03:38,860 --> 00:03:39,270 how to do it. 81 00:03:39,270 --> 00:03:41,670 You say, well, what's the x value that makes 82 00:03:41,670 --> 00:03:43,680 this equal to 0? 83 00:03:43,680 --> 00:03:46,860 Well, in order for this term to be 0, x minus 4 has to be 84 00:03:46,860 --> 00:03:48,130 equal to 0. 85 00:03:48,130 --> 00:03:51,950 x minus 4 has to be equal to 0, or add 4 to both sides. x 86 00:03:51,950 --> 00:03:53,530 has to be equal to 4. 87 00:03:53,530 --> 00:03:56,580 And if x is equal to 4, this is 0, this whole thing becomes 88 00:03:56,580 --> 00:04:01,000 0, then y is equal to 21. 89 00:04:01,000 --> 00:04:04,420 So the vertex of this parabola-- I'll just do a 90 00:04:04,420 --> 00:04:08,850 quick graph right here-- the vertex of this parabola occurs 91 00:04:08,850 --> 00:04:11,960 at the point 4, 21. 92 00:04:11,960 --> 00:04:13,500 So I'll draw it like this. 93 00:04:13,500 --> 00:04:16,480 Occurs at the point. 94 00:04:16,480 --> 00:04:21,550 If this is the point 4, if this right here is the-- so 95 00:04:21,550 --> 00:04:23,960 this is the y-axis, that's the x-axis-- so this is 96 00:04:23,960 --> 00:04:25,920 the point 4, 21. 97 00:04:25,920 --> 00:04:28,590 Now, that's either going to be the minimum or the maximum 98 00:04:28,590 --> 00:04:31,860 point in our parabola, and to think about whether it's the 99 00:04:31,860 --> 00:04:34,280 minimum or maximum point, think about what happens. 100 00:04:34,280 --> 00:04:36,300 Let's explore this equation a little bit. 101 00:04:36,300 --> 00:04:44,040 This thing, this x minus 4 squared is always greater than 102 00:04:44,040 --> 00:04:45,170 or equal to 0. 103 00:04:45,170 --> 00:04:45,510 Right? 104 00:04:45,510 --> 00:04:48,330 At worst it could be 0, but you're taking a square, so 105 00:04:48,330 --> 00:04:50,560 it's going to be a non-negative number. 106 00:04:50,560 --> 00:04:52,160 But when you take a non-negative number, and then 107 00:04:52,160 --> 00:04:55,860 you multiply it by negative 3, that guarantees that this 108 00:04:55,860 --> 00:05:00,660 whole thing is going to be less than or equal to 0. 109 00:05:00,660 --> 00:05:04,750 110 00:05:04,750 --> 00:05:07,550 So the best, the highest, value that this function can 111 00:05:07,550 --> 00:05:10,360 attain, is when this expression right 112 00:05:10,360 --> 00:05:11,630 here is equal to 0. 113 00:05:11,630 --> 00:05:13,680 And this expression is equal to 0 when x is equal 114 00:05:13,680 --> 00:05:14,810 to 4 and y is 21. 115 00:05:14,810 --> 00:05:18,360 So this is the highest value that the function can attain. 116 00:05:18,360 --> 00:05:20,660 It can only go down from there. 117 00:05:20,660 --> 00:05:24,510 Because if you shift the x around 4, then this expression 118 00:05:24,510 --> 00:05:27,850 right here will become, well, it'll become non-zero. 119 00:05:27,850 --> 00:05:29,910 When you square it, it'll become positive. 120 00:05:29,910 --> 00:05:31,225 When you multiply it by negative 3, 121 00:05:31,225 --> 00:05:32,360 it'll become negative. 122 00:05:32,360 --> 00:05:34,600 So you're going to take a negative number plus 21, it'll 123 00:05:34,600 --> 00:05:37,490 be less than 21, so your parabola is going 124 00:05:37,490 --> 00:05:38,730 to look like this. 125 00:05:38,730 --> 00:05:44,160 Your parabola is going to look like that. 126 00:05:44,160 --> 00:05:47,330 And that's why vertex form is useful. 127 00:05:47,330 --> 00:05:52,970 You break it up into the part of the equation that changes 128 00:05:52,970 --> 00:05:54,000 in value, and say, well, what's its 129 00:05:54,000 --> 00:05:56,130 maximum value attained? 130 00:05:56,130 --> 00:05:57,150 That's the vertex. 131 00:05:57,150 --> 00:05:58,670 That happens when x is equal to 4. 132 00:05:58,670 --> 00:06:00,320 And you know its y value. 133 00:06:00,320 --> 00:06:02,800 And because you have a negative coefficient out here 134 00:06:02,800 --> 00:06:05,710 that's a negative 3, you know that it's going to be a 135 00:06:05,710 --> 00:06:06,980 downward opening graph. 136 00:06:06,980 --> 00:06:09,560 If that was a positive 3, then this thing would be, at 137 00:06:09,560 --> 00:06:13,160 minimum, 0 and it would be an upward opening graph. 138 00:06:13,160 --> 00:06:13,466