1 00:00:00,650 --> 00:00:06,200 Is (3, -4) a solution to the equation 5x + 2y = 7? 2 00:00:06,200 --> 00:00:07,067 So they're saying, 3 00:00:07,067 --> 00:00:12,957 "Does x equal 3, y equal negative 4 satisfy this equation, or this relationship right here?" 4 00:00:12,957 --> 00:00:16,997 So one way to do it is to substitute x is equal to 3 and y is equal to negative 4 into this 5 00:00:16,997 --> 00:00:20,733 and see if 5 times x plus 2 times y does indeed equal 7 6 00:00:20,733 --> 00:00:26,467 So we have 5 times 3 plus 2 times -4 7 00:00:26,467 --> 00:00:34,267 This is equal to 15 plus -8, which does indeed equal 7. 8 00:00:34,267 --> 00:00:36,533 So it does satisfy the equations. 9 00:00:36,533 --> 00:00:39,400 So it is on the line; it is a solution. 10 00:00:39,400 --> 00:00:43,607 x = 3, y = -4 is a solution to this equation. 11 00:00:43,607 --> 00:00:45,353 So we've essentially answered our question: It is. 12 00:00:45,353 --> 00:00:47,333 Now another way to do it, 13 00:00:47,333 --> 00:00:49,267 and I'm not gonna go into details here, 14 00:00:49,267 --> 00:00:51,133 is you can actually graph the line. 15 00:00:51,133 --> 00:00:53,034 So maybe the line might look something like this, 16 00:00:53,034 --> 00:00:54,288 I'm not gonna do it in detail, 17 00:00:54,288 --> 00:00:57,446 and you see, if you have a very good drawing of it, 18 00:00:57,467 --> 00:00:59,533 you see whether the point lies on the line. 19 00:00:59,533 --> 00:01:02,333 If the point, when you graph the point, does lie on the line, 20 00:01:02,333 --> 00:01:03,533 it would be a solution. 21 00:01:03,533 --> 00:01:06,000 If the point somehow ends up not being on the line, 22 00:01:06,000 --> 00:01:07,733 then you'd know it isn't a solution. 23 00:01:07,733 --> 00:01:09,733 But to do this, you would have to have a very good drawing, 24 00:01:09,733 --> 00:01:12,400 so you could very precisely determine 25 00:01:12,400 --> 00:01:13,467 whether it's on the line. 26 00:01:13,467 --> 00:01:15,067 If you do the substitution method, 27 00:01:15,067 --> 00:01:17,369 if you just substitute the values into the equation 28 00:01:17,369 --> 00:01:18,667 to see if it comes out mathematically, 29 00:01:18,667 --> 00:01:20,620 this will always be exact. 30 00:01:20,620 --> 00:01:22,267 So this is all we really had to do, 31 00:01:22,267 --> 00:01:24,867 all we really have to do in this example. 32 00:01:24,867 --> 00:01:28,867 So it definitely is a solution to the equation