1 00:00:00,000 --> 00:00:00,710 2 00:00:00,710 --> 00:00:04,189 Write an inequality that fits the graph shown below. 3 00:00:04,190 --> 00:00:07,520 So here they've graphed a line in red, and the inequality 4 00:00:07,519 --> 00:00:10,279 includes this line because it's in bold red. 5 00:00:10,279 --> 00:00:12,379 It's not a dashed line. 6 00:00:12,380 --> 00:00:14,720 It's going to be all of the area above it. 7 00:00:14,720 --> 00:00:17,600 So it's all the area y is going to be greater than or 8 00:00:17,600 --> 00:00:19,530 equal to this line. 9 00:00:19,530 --> 00:00:20,630 So first we just have to figure out the 10 00:00:20,629 --> 00:00:21,679 equation of this line. 11 00:00:21,679 --> 00:00:23,359 We can figure out its y-intercept just 12 00:00:23,359 --> 00:00:24,469 by looking at it. 13 00:00:24,469 --> 00:00:26,469 Its y-intercept is right there. 14 00:00:26,469 --> 00:00:28,479 Let me do that in a darker color. 15 00:00:28,480 --> 00:00:31,879 Its y-intercept is right there at y is equal to negative 2. 16 00:00:31,879 --> 00:00:34,530 That's the point 0, negative 2. 17 00:00:34,530 --> 00:00:36,550 So if you think about this line, if you think about its 18 00:00:36,549 --> 00:00:41,439 equation as being of the form y is equal to mx plus b in 19 00:00:41,439 --> 00:00:43,679 slope-intercept form, we figured out b is equal to 20 00:00:43,679 --> 00:00:45,049 negative 2. 21 00:00:45,049 --> 00:00:47,559 So that is negative 2 right there. 22 00:00:47,560 --> 00:00:51,429 And let's think about its slope. 23 00:00:51,429 --> 00:00:58,530 If we move 2 in the x-direction, if delta x is 24 00:00:58,530 --> 00:01:01,960 equal to 2, if our change in x is positive 2, what is our 25 00:01:01,960 --> 00:01:02,990 change in y? 26 00:01:02,990 --> 00:01:08,850 Our change in y is equal to negative 1. 27 00:01:08,849 --> 00:01:16,559 Slope, or this m, is equal to change in y over change in x, 28 00:01:16,560 --> 00:01:21,280 which is equal to, in this case, negative 1 over 2, or 29 00:01:21,280 --> 00:01:22,670 negative 1/2. 30 00:01:22,670 --> 00:01:24,359 And just to reinforce, you could have done this anywhere. 31 00:01:24,359 --> 00:01:27,799 You could have said, hey, what happens if I go back 4 in x? 32 00:01:27,799 --> 00:01:34,450 So if I went back 4, if delta x was negative 4, if delta x 33 00:01:34,450 --> 00:01:38,329 is equal to negative 4, then delta y is 34 00:01:38,329 --> 00:01:39,579 equal to positive 2. 35 00:01:39,579 --> 00:01:42,299 36 00:01:42,299 --> 00:01:49,019 And once again, delta y over delta x would be positive 2 37 00:01:49,019 --> 00:01:52,700 over negative 4, which is also negative 1/2. 38 00:01:52,700 --> 00:01:55,620 I just want to reinforce that it's not dependent on how far 39 00:01:55,620 --> 00:01:58,370 I move along in x or whether I go forward or backward. 40 00:01:58,370 --> 00:02:00,840 You're always going to get or you should always get, the 41 00:02:00,840 --> 00:02:01,659 same slope. 42 00:02:01,659 --> 00:02:03,030 It's negative 1/2. 43 00:02:03,030 --> 00:02:08,150 So the equation of that line is y is equal to the slope, 44 00:02:08,150 --> 00:02:13,050 negative 1/2x, plus the y-intercept, minus 2. 45 00:02:13,050 --> 00:02:16,530 That's the equation of this line right there. 46 00:02:16,530 --> 00:02:19,939 Now, this inequality includes that line and everything above 47 00:02:19,939 --> 00:02:21,490 it for any x value. 48 00:02:21,490 --> 00:02:23,950 Let's say x is equal to 1. 49 00:02:23,949 --> 00:02:26,750 This line will tell us-- well, let's take this point so we 50 00:02:26,750 --> 00:02:27,770 get to an integer. 51 00:02:27,770 --> 00:02:29,360 Let's say that x is equal to 2. 52 00:02:29,360 --> 00:02:32,590 Let me get rid of that 1. 53 00:02:32,590 --> 00:02:35,189 When x is equal to 2, this value is going to give us 54 00:02:35,189 --> 00:02:38,534 negative 1/2 times 2, which is negative 1, minus 2, is going 55 00:02:38,534 --> 00:02:41,549 to give us negative 3. 56 00:02:41,550 --> 00:02:44,620 But this inequality isn't just y is equal to negative 3. 57 00:02:44,620 --> 00:02:48,289 y would be negative 3 or all of the values greater than 58 00:02:48,289 --> 00:02:48,900 negative 3. 59 00:02:48,900 --> 00:02:50,500 I know that, because they shaded in this 60 00:02:50,500 --> 00:02:52,180 whole area up here. 61 00:02:52,180 --> 00:02:54,920 So the equation, or, as I should say, the inequality 62 00:02:54,919 --> 00:03:00,369 that fits the graph here below is-- and I'll do it in a bold 63 00:03:00,370 --> 00:03:03,969 color-- is y is greater than or equal to 64 00:03:03,969 --> 00:03:07,680 negative 1/2x minus 2. 65 00:03:07,680 --> 00:03:12,599 That is the inequality that is depicted in this graph, where 66 00:03:12,599 --> 00:03:16,180 this is just the line, but we want all of the area above and 67 00:03:16,180 --> 00:03:17,219 equal to the line. 68 00:03:17,219 --> 00:03:19,599 So that's what we have for the inequality. 69 00:03:19,599 --> 00:03:19,733