1 00:00:02,400 --> 00:00:04,267 In this problem they are telling us the distance the 2 00:00:04,267 --> 00:00:06,733 object travels in outer space is varies directly with 3 00:00:06,733 --> 00:00:13,267 the amount of time it travels. I guess you are talking 4 00:00:13,267 --> 00:00:24,800 about a specific object. 5 00:00:24,800 --> 00:00:30,600 You think of it in terms of constants of proportionality 6 00:00:30,600 --> 00:00:39,333 you can say that the distance = some constant (k) x t 7 00:00:39,333 --> 00:00:47,133 t= time it travels for this particular object. 8 00:00:47,133 --> 00:00:53,667 if an asteroid travels 3000 miles in 6 hours 9 00:00:53,667 --> 00:00:56,333 what is the constant of variation 10 00:00:56,333 --> 00:01:03,800 So the distance is 3000; d = 3000 miles 11 00:01:03,800 --> 00:01:13,733 3000 = (k) x 6 hours. 12 00:01:13,733 --> 00:01:20,000 So to solve for constant divide both sides by 6hours 13 00:01:20,000 --> 00:01:32,000 so 3000 / 6 = 500 and 6/6 = 1 14 00:01:32,000 --> 99:59:59,999 So the constant of proportionality is 500miles/hour