1 00:00:00,998 --> 00:00:04,110 Factor t squared plus 8t plus 15. 2 00:00:04,110 --> 00:00:07,268 So let's just think about what happen if we multiply 2 binomials 3 00:00:07,268 --> 00:00:10,751 t plus a times t plus b 4 00:00:10,751 --> 00:00:13,769 And I'm using t here because t is the variable in the polynomial 5 00:00:13,769 --> 00:00:16,556 that we need to factor. So if you multiply this out, 6 00:00:16,556 --> 00:00:20,225 applying de distributive property twice or using F.O.I.L, 7 00:00:20,225 --> 00:00:25,519 You get t times t which is t squared plus t times b 8 00:00:25,519 --> 00:00:31,742 which is bt plus a times t which is at plus a times b 9 00:00:31,742 --> 00:00:35,085 which is ab. We essentialy multiplied every term here by 10 00:00:35,085 --> 00:00:39,358 every term over there. And then we have 2 terms, 2 t terms 11 00:00:39,358 --> 00:00:41,726 I guess we could call them. This bt plus at. 12 00:00:41,726 --> 00:00:44,559 So we can combine those. So we get t squared 13 00:00:44,559 --> 00:00:49,342 plus a plus b t, I can write this is b plus a t as well. 14 00:00:49,342 --> 00:00:55,380 plus ab. If we compare this to this right over here. 15 00:00:55,380 --> 00:00:57,191 we see that we have a similar pattern. 16 00:00:57,191 --> 00:01:00,860 Our coeffient, Our coeffient on the second degree term is one 17 00:01:00,860 --> 00:01:04,110 Our coeffient on the second degree term here is one. 18 00:01:04,110 --> 00:01:07,918 We didn't have to write it. Then, a plus b is a coefficient on t. 19 00:01:07,918 --> 00:01:12,330 So 8, right over here, this 8 could be a plus b. 20 00:01:12,330 --> 00:01:16,835 And then finally, our constant term ab that could be 15. 21 00:01:16,835 --> 00:01:20,689 That could be 15. So if we want to factor this out. 22 00:01:20,689 --> 00:01:24,637 We just have to find an a and a b where their product is 15 23 00:01:24,637 --> 00:01:29,374 and their sum is 8. In general, in general if you ever see 24 00:01:29,374 --> 00:01:32,253 I'll write it in kind of the more traditional with the x variable 25 00:01:32,253 --> 00:01:38,151 If you see anything of the form x squared plus bx plus c. 26 00:01:38,151 --> 00:01:42,237 The coefficient here is 1. Then you just have to find 27 00:01:42,237 --> 00:01:46,835 2 numbers whose sum is equal to this thing right here 28 00:01:46,885 --> 00:01:49,946 and his whose product is equal that thing right there. 29 00:01:49,946 --> 00:01:54,358 Whose sum is equal to 8 and whose product is equal to 15 30 00:01:54,358 --> 00:01:56,820 So what are 2 numbers that add up to 8 and 31 00:01:56,820 --> 00:01:59,699 whose product are 15. So if we just factor 15, 32 00:01:59,699 --> 00:02:02,950 We have 1 and 15. Those don't add up to 8 in anyway. 33 00:02:02,950 --> 00:02:06,154 3 and 5. Those do add up to 8. 34 00:02:06,154 --> 00:02:10,519 So a and b could be 3 and 5, So a and b, 35 00:02:10,519 --> 00:02:15,070 this could be 3 times 5 and then 8 is 3 plus 5. 36 00:02:15,070 --> 00:02:17,903 Now we can just go straight and factor this and say, hey, 37 00:02:17,903 --> 00:02:22,362 This is t plus 3 time t plus 5. Since we already figured out what a and b are. 38 00:02:22,362 --> 00:02:26,495 But what I want to do is kind of factor this by grouping. 39 00:02:26,495 --> 00:02:29,745 So, I'm essentially going to go in reverse step. 40 00:02:29,745 --> 00:02:33,321 From what I just showed you. So this first, this polynomial right here, 41 00:02:33,321 --> 00:02:37,362 I'm going to write it as t squared plus, instead of 42 00:02:37,362 --> 00:02:41,355 8t i'm going to write it as a sum of at plus bt. 43 00:02:41,355 --> 00:02:47,486 Or as a sum of 3 t plus 5 t. So plus 3t plus 5t. 44 00:02:47,486 --> 00:02:51,061 So, I'm essentially, I starded here and I'm going to this step 45 00:02:51,061 --> 00:02:55,659 where I break up that middle term into the coefficients 46 00:02:55,659 --> 00:02:58,863 that add up to the 8. And then finally plus 15. 47 00:02:58,863 --> 00:03:01,232 and now, I can factor by grouping. 48 00:03:01,232 --> 00:03:04,483 These 2 guys right over here have a common factor t. 49 00:03:04,483 --> 00:03:07,919 And these 2 guys over here have a common factor 5. 50 00:03:07,919 --> 00:03:11,495 So let's factor out the t in this first expression over here 51 00:03:11,495 --> 00:03:16,418 or this part of the expression. So it's t times t plus 3 plus 52 00:03:16,418 --> 00:03:19,761 and then over here if you factor out a 5, you get a 5. 53 00:03:19,761 --> 00:03:27,145 times t plus 3, 5t divided by 5 is t, 15 divided by 5 is 3. 54 00:03:27,145 --> 00:03:29,746 And now you can factor out a t plus 3. 55 00:03:29,746 --> 00:03:33,972 You have a t plus 3 being multplying times both of these terms 56 00:03:33,972 --> 00:03:36,619 So, let's factor, let's factor that out. 57 00:03:36,619 --> 00:03:43,121 So it becomes t plus 3 times, times, t plus 5 58 00:03:43,121 --> 00:03:46,278 times, I'll write that plus a little bit neater, 59 00:03:46,278 --> 00:03:54,405 times t plus 5. And we are done. We didn't actually 60 00:03:54,405 --> 00:03:56,913 have to do this grouping step altough hopefully you see 61 00:03:56,913 --> 00:03:58,910 that it does work. We could have just said look 62 00:03:58,910 --> 00:04:01,789 from this pattern over here I have two numbers 63 00:04:01,789 --> 00:04:04,158 that add up to 8 and their product is 15. 64 00:04:04,158 --> 99:59:59,999 So, this is t plus 3 times t plus 5. or t plus 5 times t plus 3 either way