1 00:00:00,000 --> 00:00:01,850 2 00:00:01,850 --> 00:00:05,900 Welcome to the presentation on quadratic inequalities. 3 00:00:05,900 --> 00:00:09,660 Before we get to quadratic inequalities, let's just start 4 00:00:09,660 --> 00:00:11,945 graphing some functions and interpret them and then we'll 5 00:00:11,945 --> 00:00:13,880 slowly move to the inequalities. 6 00:00:13,880 --> 00:00:26,359 Let's say I had f of x is equal to x squared plus x minus 6. 7 00:00:26,359 --> 00:00:29,210 Well, if we wanted to figure out where this function 8 00:00:29,210 --> 00:00:33,070 intersects the x-axis or the roots of it, we learned in our 9 00:00:33,070 --> 00:00:35,210 factoring quadratics that we could just set f of x 10 00:00:35,210 --> 00:00:36,734 is equal to 0, right? 11 00:00:36,734 --> 00:00:39,460 Because f of x equals 0 when you're intersecting the x-axis. 12 00:00:39,460 --> 00:00:46,990 So you would say x squared plus x minus 6 is equal to 0. 13 00:00:46,990 --> 00:00:48,800 And you just factor this quadratic. 14 00:00:48,799 --> 00:00:57,469 x plus 3 times x minus 2 equals 0. 15 00:00:57,469 --> 00:01:03,269 And you would learn that the roots of this quadratic 16 00:01:03,270 --> 00:01:11,600 function are x is equal to minus 3, and x is equal to 2. 17 00:01:11,599 --> 00:01:13,969 How would we visualize this? 18 00:01:13,969 --> 00:01:16,969 Well let's draw this quadratic function. 19 00:01:16,969 --> 00:01:21,379 20 00:01:21,379 --> 00:01:24,509 Those are my very uneven lines. 21 00:01:24,510 --> 00:01:27,200 So the roots are x is equal to negative 3. 22 00:01:27,200 --> 00:01:33,180 So this is, right here, x is at minus 3y0 -- by definition one 23 00:01:33,180 --> 00:01:36,790 of the roots is where f of x is equal to 0. 24 00:01:36,790 --> 00:01:41,370 So the y, or the f of x axis here is 0. 25 00:01:41,370 --> 00:01:42,600 The coordinate is 0. 26 00:01:42,599 --> 00:01:47,129 And this point here is 2 comma 0. 27 00:01:47,129 --> 00:01:53,359 Once again, this is the x-axis, and this is the f of x-axis. 28 00:01:53,359 --> 00:01:56,269 We also know that the y intercept is minus 6. 29 00:01:56,269 --> 00:01:57,799 This isn't the vertex, this is the y intercept. 30 00:01:57,799 --> 00:02:03,709 And that the graph is going to look something like this -- not 31 00:02:03,709 --> 00:02:05,640 as bumpy as what I'm drawing, which I think you get the 32 00:02:05,640 --> 00:02:10,180 general idea if you've ever seen a clean parabola. 33 00:02:10,180 --> 00:02:16,200 It looks like that with x minus 3 here, and x is 2 here. 34 00:02:16,199 --> 00:02:17,079 Pretty straightforward. 35 00:02:17,080 --> 00:02:19,480 We figured out the roots, we figured out what it looks like. 36 00:02:19,479 --> 00:02:22,169 Now what if we, instead of wanting to know where f of x is 37 00:02:22,169 --> 00:02:24,959 equal to 0, which is these two points, what if we wanted 38 00:02:24,960 --> 00:02:29,290 to know where f of x is greater than 0? 39 00:02:29,289 --> 00:02:33,199 What x values make f of x greater than 0? 40 00:02:33,199 --> 00:02:36,049 Or another way of saying it, what values make 41 00:02:36,050 --> 00:02:37,410 the statement true? 42 00:02:37,409 --> 00:02:42,740 x squared plus x minus 6 is greater than 0, Right, 43 00:02:42,740 --> 00:02:44,730 this is just f of x. 44 00:02:44,729 --> 00:02:49,469 Well if we look at the graph, when is f of x greater than 0? 45 00:02:49,469 --> 00:02:52,009 Well this is the f of x axis, and when are we 46 00:02:52,009 --> 00:02:52,909 in positive territory? 47 00:02:52,909 --> 00:02:55,359 Well f of x is greater than 0 here -- let me draw that 48 00:02:55,360 --> 00:03:00,890 another color -- is greater than 0 here, right? 49 00:03:00,889 --> 00:03:04,979 Because it's above the x-axis. 50 00:03:04,979 --> 00:03:06,829 And f of x is greater than 0 here. 51 00:03:06,830 --> 00:03:11,560 52 00:03:11,560 --> 00:03:17,069 So just visually looking at it, what x values make this true? 53 00:03:17,069 --> 00:03:23,579 Well, this is true whenever x is less than minus 3, right, or 54 00:03:23,580 --> 00:03:26,440 whenever x is greater than 2. 55 00:03:26,439 --> 00:03:31,560 Because when x is greater than 2, f of x is greater than 0, 56 00:03:31,560 --> 00:03:35,909 and when x is less than negative 3, f of x 57 00:03:35,909 --> 00:03:37,430 is greater than 0. 58 00:03:37,430 --> 00:03:41,460 So we would say the solution to this quadratic inequality, and 59 00:03:41,460 --> 00:03:46,909 we pretty much solved this visually, is x is less than 60 00:03:46,909 --> 00:03:52,969 minus 3, or x is greater than 2. 61 00:03:52,969 --> 00:03:53,889 And you could test it out. 62 00:03:53,889 --> 00:03:56,989 You could try out the number minus 4, and you should get f 63 00:03:56,990 --> 00:03:58,800 of x being greater than 0. 64 00:03:58,800 --> 00:04:00,890 You could try it out here. 65 00:04:00,889 --> 00:04:04,109 Or you could try the number 3 and make sure that this works. 66 00:04:04,110 --> 00:04:06,820 And you can just make sure that, you could, for example, 67 00:04:06,819 --> 00:04:10,409 try out the number 0 and make sure that 0 doesn't work, 68 00:04:10,409 --> 00:04:12,789 right, because 0 is between the two roots. 69 00:04:12,789 --> 00:04:15,030 It actually turns out that when x is equal to 0, f 70 00:04:15,030 --> 00:04:19,040 of x is minus 6, which is definitely less than 0. 71 00:04:19,040 --> 00:04:22,400 So I think this will give you a visual intuition of what this 72 00:04:22,399 --> 00:04:24,000 quadratic inequality means. 73 00:04:24,000 --> 00:04:26,509 Now with that visual intuition in the back of your mind, let's 74 00:04:26,509 --> 00:04:29,089 do some more problems and maybe we won't have to go through the 75 00:04:29,089 --> 00:04:32,599 exercise of drawing it, but maybe I will draw it just to 76 00:04:32,600 --> 00:04:35,189 make sure that the point hits home. 77 00:04:35,189 --> 00:04:37,139 Let me give you a slightly trickier problem. 78 00:04:37,139 --> 00:04:49,120 Let's say I had minus x squared minus 3x plus 28, let me 79 00:04:49,120 --> 00:04:52,189 say, is greater than 0. 80 00:04:52,189 --> 00:04:53,600 Well I want to get rid of this negative sign in 81 00:04:53,600 --> 00:04:54,350 front of the x squared. 82 00:04:54,350 --> 00:04:56,420 I just don't like it there because it makes it look 83 00:04:56,420 --> 00:04:58,080 more confusing to factor. 84 00:04:58,079 --> 00:05:00,139 I'm going to multiply everything by negative 1. 85 00:05:00,139 --> 00:05:00,779 Both sides. 86 00:05:00,779 --> 00:05:08,209 I get x squared plus 3x minus 28, and when you multiply or 87 00:05:08,209 --> 00:05:10,159 divide by a negative, with any inequality you have 88 00:05:10,160 --> 00:05:11,439 to swap the sign. 89 00:05:11,439 --> 00:05:16,860 So this is now going to be less than 0. 90 00:05:16,860 --> 00:05:25,129 And if we were to factor this, we get x plus 7 times x 91 00:05:25,129 --> 00:05:29,879 minus 4 is less than 0. 92 00:05:29,879 --> 00:05:32,459 So if this was equal to 0, we would know that the two roots 93 00:05:32,459 --> 00:05:37,399 of this function -- let's define the function f of x -- 94 00:05:37,399 --> 00:05:40,539 let's define the function as f of x is equal to -- well we can 95 00:05:40,540 --> 00:05:42,670 define it as this or this because they're the same thing. 96 00:05:42,670 --> 00:05:47,080 But for simplicity let's define it as x plus 7 times x minus 4. 97 00:05:47,079 --> 00:05:49,389 That's f of x, right? 98 00:05:49,389 --> 00:05:53,259 Well, after factoring it, we know that the roots of this, 99 00:05:53,259 --> 00:06:05,599 the roots are x is equal to minus 7, and x is equal to 4. 100 00:06:05,600 --> 00:06:07,900 Now what we want to know is what x values make 101 00:06:07,899 --> 00:06:10,000 this inequality true? 102 00:06:10,000 --> 00:06:12,060 If this was any equality we'd be done. 103 00:06:12,060 --> 00:06:14,649 But we want to know what makes this inequality true. 104 00:06:14,649 --> 00:06:17,599 I'll give you a little bit of a trick, it's always going to be 105 00:06:17,600 --> 00:06:21,160 the numbers in between the two roots or outside 106 00:06:21,160 --> 00:06:23,120 of the two roots. 107 00:06:23,120 --> 00:06:25,810 So what I do whenever I'm doing this on a test or something, I 108 00:06:25,810 --> 00:06:28,509 just test numbers that are either between the roots or 109 00:06:28,509 --> 00:06:30,610 outside of the two roots. 110 00:06:30,610 --> 00:06:34,660 So let's pick a number that's between x equals minus 111 00:06:34,660 --> 00:06:36,360 7 and x equals 4. 112 00:06:36,360 --> 00:06:41,560 Well let's try x equals 0. 113 00:06:41,560 --> 00:06:46,660 Well, f of 0 is equal to -- we could do it right here -- f of 114 00:06:46,660 --> 00:06:57,360 0 is 0 plus 7 times 0 minus 4 is just 7 times minus 115 00:06:57,360 --> 00:07:00,280 4, which is minus 28. 116 00:07:00,279 --> 00:07:04,099 So f of 0 is minus 28. 117 00:07:04,100 --> 00:07:08,800 Now is this -- this is the function we're working with 118 00:07:08,800 --> 00:07:11,790 -- is this less than 0? 119 00:07:11,790 --> 00:07:13,140 Well yeah, it is. 120 00:07:13,139 --> 00:07:16,089 So it actually turns that a number, an x value between 121 00:07:16,089 --> 00:07:17,469 the two roots works. 122 00:07:17,470 --> 00:07:19,940 So actually I immediately know that the answer here 123 00:07:19,939 --> 00:07:23,339 is all of the x's that are between the two roots. 124 00:07:23,339 --> 00:07:29,169 So we could say that the solution to this is 125 00:07:29,170 --> 00:07:34,720 minus 7 is less than x which is less than 4. 126 00:07:34,720 --> 00:07:35,460 Because now the other way. 127 00:07:35,459 --> 00:07:38,239 You could have tried a number that's outside of the roots, 128 00:07:38,240 --> 00:07:41,460 either less than minus 7 or greater than 4 and 129 00:07:41,459 --> 00:07:42,649 have tried it out. 130 00:07:42,649 --> 00:07:45,819 Let's say if you had tried out 5. 131 00:07:45,819 --> 00:07:48,139 Try x equals 5. 132 00:07:48,139 --> 00:07:55,779 Well then f of 5 would be 12 times 1, right, 133 00:07:55,779 --> 00:07:58,689 which is equal to 12. 134 00:07:58,689 --> 00:07:59,569 f of 5 is 12. 135 00:07:59,569 --> 00:08:02,300 Is that less than 0? 136 00:08:02,300 --> 00:08:03,110 No. 137 00:08:03,110 --> 00:08:04,060 So that wouldn't have worked. 138 00:08:04,060 --> 00:08:06,000 So once again, that gives us a confidence that we 139 00:08:06,000 --> 00:08:07,259 got the right interval. 140 00:08:07,259 --> 00:08:11,750 And if we wanted to think about this visually, because we got 141 00:08:11,750 --> 00:08:14,920 this answer, when you do it visually it actually makes, I 142 00:08:14,920 --> 00:08:18,640 think, a lot of sense, but maybe I'm biased. 143 00:08:18,639 --> 00:08:26,180 144 00:08:26,180 --> 00:08:28,769 If you look at it visually it looks like this. 145 00:08:28,769 --> 00:08:35,129 146 00:08:35,129 --> 00:08:40,889 If you drive visually and this is the parabola, this is f of 147 00:08:40,889 --> 00:08:52,580 x, the roots here are minus 7, 0 and 4, 0, we're saying that 148 00:08:52,580 --> 00:08:56,230 for all x values between these two numbers, f of 149 00:08:56,230 --> 00:08:57,389 x is less than 0. 150 00:08:57,389 --> 00:08:59,769 And that makes sense, because when is f of x less than 0? 151 00:08:59,769 --> 00:09:02,419 Well this is the graph of f of x. 152 00:09:02,419 --> 00:09:06,110 153 00:09:06,110 --> 00:09:07,570 And when is f of x less than 0? 154 00:09:07,570 --> 00:09:08,480 Right here. 155 00:09:08,480 --> 00:09:10,879 So what x values give us that? 156 00:09:10,879 --> 00:09:14,139 Well the x values that give us that are right here. 157 00:09:14,139 --> 00:09:15,409 I hope I'm not confusing you too much with 158 00:09:15,409 --> 00:09:16,959 these visual graphs. 159 00:09:16,960 --> 00:09:19,139 And you're probably saying, well how do I know 160 00:09:19,139 --> 00:09:20,179 I don't include 0? 161 00:09:20,179 --> 00:09:23,115 Well you could try it out, but if you -- oh, well how come 162 00:09:23,115 --> 00:09:24,689 I don't include the roots? 163 00:09:24,690 --> 00:09:28,030 Well at the roots, f of x is equal to 0. 164 00:09:28,029 --> 00:09:31,639 So if this was this, if this was less than or equal to 0, 165 00:09:31,639 --> 00:09:36,289 then the answer would be negative 7 is less than 166 00:09:36,289 --> 00:09:39,230 or equal to x is less than or equal to 4. 167 00:09:39,230 --> 00:09:40,620 I hope that gives you a sense. 168 00:09:40,620 --> 00:09:42,460 You pretty much just have to try number in between the 169 00:09:42,460 --> 00:09:45,250 roots, and try number outside of the roots, and that tells 170 00:09:45,250 --> 00:09:49,299 you what interval will make the inequality true. 171 00:09:49,299 --> 00:09:51,639 I'll see you in the next presentation. 172 00:09:51,639 --> 00:09:51,986