1 99:59:59,999 --> 99:59:59,999 Let's now attempt to apply Stokes' theorem 2 99:59:59,999 --> 99:59:59,999 And so over here we have this little diagram, and we have this path 3 99:59:59,999 --> 99:59:59,999 that we're calling C, and it's the intersection of the plain Y+Z=2, so that's the plain that 4 99:59:59,999 --> 99:59:59,999 kind of slants down like that, its the intersection of that plain 5 99:59:59,999 --> 99:59:59,999 and the cylinder, you know I shouldn't even call it a cylinder 6 99:59:59,999 --> 99:59:59,999 because if you just have x^2 plus y^2 is equal to one, it would essentially be like a pole, 7 99:59:59,999 --> 99:59:59,999 an infinite pole that keeps going up forever and keeps going down forever 8 99:59:59,999 --> 99:59:59,999 so it would never have a top or a bottom 9 99:59:59,999 --> 99:59:59,999 but we slice that pole, with y plus z is equal to 2, to get where they intersect 10 99:59:59,999 --> 99:59:59,999 we get our path C. We also have this vector field defined in this way