1 00:00:00,000 --> 00:00:01,080 2 00:00:01,080 --> 00:00:03,790 Welcome to the presentation on derivatives. 3 00:00:03,790 --> 00:00:06,290 I think you're going to find that this is when math starts 4 00:00:06,290 --> 00:00:10,530 to become a lot more fun than it was just a few topics ago. 5 00:00:10,529 --> 00:00:11,989 Well let's get started with our derivatives. 6 00:00:11,990 --> 00:00:13,150 I know it sounds very complicated. 7 00:00:13,150 --> 00:00:16,560 Well, in general, if I have a straight line-- let me see if I 8 00:00:16,559 --> 00:00:20,989 can draw a straight line properly-- if I had a straight 9 00:00:20,989 --> 00:00:28,019 line-- that's my coordinate axes, which aren't straight-- 10 00:00:28,019 --> 00:00:29,120 this is a straight line. 11 00:00:29,120 --> 00:00:31,700 12 00:00:31,699 --> 00:00:34,630 But when I have a straight line like that, and I ask you to 13 00:00:34,630 --> 00:00:37,150 find the slope-- I think you already know how to do this-- 14 00:00:37,149 --> 00:00:39,539 it's just the change in y divided by the change in x. 15 00:00:39,539 --> 00:00:43,799 If I wanted to find the slope-- really I mean the slope is the 16 00:00:43,799 --> 00:00:46,140 same, because it is a straight line, the slope is the same 17 00:00:46,140 --> 00:00:50,039 across the whole line, but if I want to find the slope at any 18 00:00:50,039 --> 00:00:51,839 point in this line, what I would do is I would pick a 19 00:00:51,840 --> 00:00:56,000 point x-- say I'd pick this point. 20 00:00:56,000 --> 00:01:00,280 We'd pick a different color-- I'd take this point, I'd pick 21 00:01:00,280 --> 00:01:02,840 this point-- it's pretty arbitrary, I could pick any two 22 00:01:02,840 --> 00:01:05,990 points, and I would figure out what the change in y is-- this 23 00:01:05,989 --> 00:01:09,859 is the change in y, delta y, that's just another way of 24 00:01:09,859 --> 00:01:15,859 saying change in y-- and this is the change in x. 25 00:01:15,859 --> 00:01:16,920 delta x. 26 00:01:16,920 --> 00:01:22,140 And we figured out that the slope is defined really as 27 00:01:22,140 --> 00:01:30,250 change in y divided by change in x. 28 00:01:30,250 --> 00:01:33,540 29 00:01:33,540 --> 00:01:37,640 And another way of saying that is delta-- it's that triangle-- 30 00:01:37,640 --> 00:01:41,180 delta y divided by delta x. 31 00:01:41,180 --> 00:01:42,660 Very straightforward. 32 00:01:42,659 --> 00:01:45,099 Now what happens, though, if we're not dealing 33 00:01:45,099 --> 00:01:45,859 with a straight line? 34 00:01:45,859 --> 00:01:49,780 Let me see if I have space to draw that. 35 00:01:49,780 --> 00:01:52,920 Another coordinate axes. 36 00:01:52,920 --> 00:01:55,780 Still pretty messy, but I think you'll get the point. 37 00:01:55,780 --> 00:02:00,073 38 00:02:00,072 --> 00:02:02,959 Now let's say, instead of just a regular line like this, this 39 00:02:02,959 --> 00:02:04,689 follows the standard y equals mx plus b. 40 00:02:04,689 --> 00:02:09,639 Let's just say I had the curve y equals x squared. 41 00:02:09,639 --> 00:02:12,149 Let me draw it in a different color. 42 00:02:12,150 --> 00:02:15,939 So y equals x squared looks something like this. 43 00:02:15,939 --> 00:02:19,319 It's a curve, you're probably pretty familiar with it by now. 44 00:02:19,319 --> 00:02:20,650 And what I'm going to ask you is, what is the 45 00:02:20,650 --> 00:02:23,180 slope of this curve? 46 00:02:23,180 --> 00:02:24,439 And think about that. 47 00:02:24,439 --> 00:02:26,930 What does it mean to take the slope of a curve now? 48 00:02:26,930 --> 00:02:29,150 Well, in this line, the slope was the same throughout 49 00:02:29,150 --> 00:02:30,400 the whole line. 50 00:02:30,400 --> 00:02:31,780 But if you look at this curve, doesn't the 51 00:02:31,780 --> 00:02:32,960 slope change, right? 52 00:02:32,960 --> 00:02:36,560 Here it's almost flat, and it gets steeper steeper steeper 53 00:02:36,560 --> 00:02:38,865 steeper steeper until gets pretty steep. 54 00:02:38,865 --> 00:02:41,000 And if you go really far out, it gets extremely steep. 55 00:02:41,000 --> 00:02:42,629 So you're probably saying, well, how do you figure out 56 00:02:42,629 --> 00:02:45,909 the slope of a curve whose slope keeps changing? 57 00:02:45,909 --> 00:02:48,169 Well there is no slope for the entire curve. 58 00:02:48,169 --> 00:02:50,899 For a line, there is a slope for the entire line, because 59 00:02:50,900 --> 00:02:52,250 the slope never changes. 60 00:02:52,250 --> 00:02:54,379 But what we could try to do is figure out what the 61 00:02:54,379 --> 00:02:56,719 slope is at a given point. 62 00:02:56,719 --> 00:02:59,539 And the slope at a given point would be the same as the 63 00:02:59,539 --> 00:03:00,889 slope of a tangent line. 64 00:03:00,889 --> 00:03:08,259 For example-- let me pick a green-- the slope at this point 65 00:03:08,259 --> 00:03:17,969 right here would be the same as the slope of this line. 66 00:03:17,969 --> 00:03:19,180 Right? 67 00:03:19,180 --> 00:03:20,550 Because this line is tangent to it. 68 00:03:20,550 --> 00:03:24,350 So it just touches that curve, and at that exact point, they 69 00:03:24,349 --> 00:03:27,819 would have-- this blue curve, y equals x squared, would have 70 00:03:27,819 --> 00:03:30,650 the same slope as this green line. 71 00:03:30,650 --> 00:03:33,050 But if we go to a point back here, even though this is a 72 00:03:33,050 --> 00:03:36,939 really badly drawn graph, the slope would be 73 00:03:36,939 --> 00:03:38,699 something like this. 74 00:03:38,699 --> 00:03:40,014 The tangent slope. 75 00:03:40,014 --> 00:03:42,519 The slope would be a negative slope, and here it's a positive 76 00:03:42,520 --> 00:03:47,939 slope, but if we took a point here, the slope would 77 00:03:47,939 --> 00:03:50,629 be even more positive. 78 00:03:50,629 --> 00:03:52,030 So how are we going to figure this out? 79 00:03:52,030 --> 00:03:55,900 How are we going to figure out what the slope is at any point 80 00:03:55,900 --> 00:03:58,849 along the curve y equals x squared? 81 00:03:58,849 --> 00:04:01,590 That's where the derivative comes into use, and now for the 82 00:04:01,590 --> 00:04:03,289 first time you'll actually see why a limit is actually 83 00:04:03,289 --> 00:04:06,009 a useful concept. 84 00:04:06,009 --> 00:04:09,129 So let me try to redraw the curve. 85 00:04:09,129 --> 00:04:15,750 OK, I'll draw my axes, that's the y-axis-- I'll just do it in 86 00:04:15,750 --> 00:04:22,629 the first quadrant-- and this is-- I really have to find a 87 00:04:22,629 --> 00:04:29,469 better tool to do my-- this is x coordinate, and then let 88 00:04:29,470 --> 00:04:31,620 me draw my curve in yellow. 89 00:04:31,620 --> 00:04:34,134 90 00:04:34,134 --> 00:04:37,789 So y equals x squared looks something like this. 91 00:04:37,790 --> 00:04:40,520 I'm really concentrating to draw this at 92 00:04:40,519 --> 00:04:41,699 least decently good. 93 00:04:41,699 --> 00:04:42,800 OK. 94 00:04:42,800 --> 00:04:46,889 So let's say we want to find the slope at this point. 95 00:04:46,889 --> 00:04:53,560 96 00:04:53,560 --> 00:05:00,040 Let's call this point a. 97 00:05:00,040 --> 00:05:02,069 At this point, x equals a. 98 00:05:02,069 --> 00:05:06,844 And of course this is f of a. 99 00:05:06,845 --> 00:05:11,340 100 00:05:11,339 --> 00:05:13,189 So what we could try to do is, we could try to find 101 00:05:13,189 --> 00:05:15,410 the slope of a secant line. 102 00:05:15,410 --> 00:05:19,920 A line between-- we take another point, say, somewhat 103 00:05:19,920 --> 00:05:26,550 close, to this point on the graph, let's say here, and if 104 00:05:26,550 --> 00:05:29,530 we could figure out the slope of this line, it would be a 105 00:05:29,529 --> 00:05:34,000 bit of an approximation of the slope of the curve 106 00:05:34,000 --> 00:05:35,089 exactly at this point. 107 00:05:35,089 --> 00:05:37,739 So let me draw that secant line. 108 00:05:37,740 --> 00:05:44,460 109 00:05:44,459 --> 00:05:45,099 Something like that. 110 00:05:45,100 --> 00:05:46,689 Secant line looks something like that. 111 00:05:46,689 --> 00:05:56,050 And let's say that this point right here is a plus h, where 112 00:05:56,050 --> 00:05:59,860 this distance is just h, this is a plus h, we're just going 113 00:05:59,860 --> 00:06:05,160 h away from a, and then this point right here 114 00:06:05,160 --> 00:06:09,060 is f of a plus h. 115 00:06:09,060 --> 00:06:11,639 116 00:06:11,639 --> 00:06:13,103 My pen is malfunctioning. 117 00:06:13,103 --> 00:06:17,730 118 00:06:17,730 --> 00:06:19,550 So this would be an approximation for what the 119 00:06:19,550 --> 00:06:21,220 slope is at this point. 120 00:06:21,220 --> 00:06:24,980 And the closer that h gets, the closer this point gets to 121 00:06:24,980 --> 00:06:27,390 this point, the better our approximation is going to be, 122 00:06:27,389 --> 00:06:30,519 all the way to the point that if we could actually get the 123 00:06:30,519 --> 00:06:34,139 slope where h equals 0, that would actually be the slope, 124 00:06:34,139 --> 00:06:37,050 the instantaneous slope, at that point in the curve. 125 00:06:37,050 --> 00:06:41,439 But how can we figure out what the slope is when h equals 0? 126 00:06:41,439 --> 00:06:44,800 127 00:06:44,800 --> 00:06:46,670 So right now, we're saying that the slope between these two 128 00:06:46,670 --> 00:06:49,900 points, it would be the change in y, so what's 129 00:06:49,899 --> 00:06:51,039 the change in y? 130 00:06:51,040 --> 00:06:57,170 It's this, so that this point right here is-- the x 131 00:06:57,170 --> 00:07:00,710 coordinate is-- my thing just keeps messing up-- the x 132 00:07:00,709 --> 00:07:11,329 coordinate is a plus h, and the y coordinate is f of a plus h. 133 00:07:11,329 --> 00:07:15,180 134 00:07:15,180 --> 00:07:22,050 And this point right here, the coordinate is a and f of a. 135 00:07:22,050 --> 00:07:25,370 So if we just use the standard slope formula, like before, we 136 00:07:25,370 --> 00:07:27,610 would say change in y over change in x. 137 00:07:27,610 --> 00:07:29,100 Well, what's the change in y? 138 00:07:29,100 --> 00:07:37,680 It's f of a plus h-- this y coordinate minus this y 139 00:07:37,680 --> 00:07:46,850 coordinate-- minus f of a over the change in x. 140 00:07:46,850 --> 00:07:53,010 Well that change in x is this x coordinate, a plus h, minus 141 00:07:53,009 --> 00:07:55,719 this x coordinate, minus a. 142 00:07:55,720 --> 00:07:58,480 And of course this a and this a cancel out. 143 00:07:58,480 --> 00:08:01,490 So it's f of a plus h, minus f of a, all over h. 144 00:08:01,490 --> 00:08:05,400 This is just the slope of this secant line. 145 00:08:05,399 --> 00:08:08,810 And if we want to get the slope of the tangent line, we would 146 00:08:08,810 --> 00:08:11,980 just have to find what happens as h gets smaller and 147 00:08:11,980 --> 00:08:12,780 smaller and smaller. 148 00:08:12,779 --> 00:08:14,469 And I think you know where I'm going. 149 00:08:14,470 --> 00:08:16,840 Really, we just want to, if we want to find the slope of this 150 00:08:16,839 --> 00:08:19,139 tangent line, we just have to find the limit of this 151 00:08:19,139 --> 00:08:28,779 value as h approaches 0. 152 00:08:28,779 --> 00:08:32,699 And then, as h approaches 0, this secant line is going to 153 00:08:32,700 --> 00:08:36,710 get closer and closer to the slope of the tangent line. 154 00:08:36,710 --> 00:08:40,590 And then we'll know the exact slope at the instantaneous 155 00:08:40,590 --> 00:08:41,899 point along the curve. 156 00:08:41,899 --> 00:08:44,149 And actually, it turns out that this is the definition 157 00:08:44,149 --> 00:08:46,799 of the derivative. 158 00:08:46,799 --> 00:08:50,779 And the derivative is nothing more than the slope of a 159 00:08:50,779 --> 00:08:53,009 curve at an exact point. 160 00:08:53,009 --> 00:08:56,309 And this is super useful, because for the first time, 161 00:08:56,309 --> 00:08:58,569 everything we've talked about to this point is 162 00:08:58,570 --> 00:08:59,560 the slope of a line. 163 00:08:59,559 --> 00:09:03,049 But now we can take any continuous curve, or most 164 00:09:03,049 --> 00:09:06,799 continuous curves, and find the slope of that curve 165 00:09:06,799 --> 00:09:08,339 at an exact point. 166 00:09:08,340 --> 00:09:11,940 So now that I've given you the definition of what a derivative 167 00:09:11,940 --> 00:09:13,690 is, and maybe hopefully a little bit of intuition, in the 168 00:09:13,690 --> 00:09:17,070 next presentation I'm going to use this definition to actually 169 00:09:17,070 --> 00:09:20,040 apply it to some functions, like x squared and others, and 170 00:09:20,039 --> 00:09:21,929 give you some more problems. 171 00:09:21,929 --> 00:09:24,069 I'll see you in the next presentation 172 00:09:24,070 --> 00:09:25,000